x^3-4x^2+mx=2

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Solution for x^3-4x^2+mx=2 equation:


Simplifying
x3 + -4x2 + mx = 2

Reorder the terms:
mx + -4x2 + x3 = 2

Solving
mx + -4x2 + x3 = 2

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '4x2' to each side of the equation.
mx + -4x2 + 4x2 + x3 = 2 + 4x2

Combine like terms: -4x2 + 4x2 = 0
mx + 0 + x3 = 2 + 4x2
mx + x3 = 2 + 4x2

Add '-1x3' to each side of the equation.
mx + x3 + -1x3 = 2 + 4x2 + -1x3

Combine like terms: x3 + -1x3 = 0
mx + 0 = 2 + 4x2 + -1x3
mx = 2 + 4x2 + -1x3

Divide each side by 'x'.
m = 2x-1 + 4x + -1x2

Simplifying
m = 2x-1 + 4x + -1x2

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